Optimal. Leaf size=211 \[ \frac{9 x \left (2 a^2 d^2+9 a b c d+54 b^2 c^2\right )}{910 a^5 b^2 \sqrt [3]{a+b x^3}}+\frac{3 x \left (2 a^2 d^2+9 a b c d+54 b^2 c^2\right )}{910 a^4 b^2 \left (a+b x^3\right )^{4/3}}+\frac{x \left (2 a^2 d^2+9 a b c d+54 b^2 c^2\right )}{455 a^3 b^2 \left (a+b x^3\right )^{7/3}}+\frac{2 x (b c-a d) (a d+3 b c)}{65 a^2 b^2 \left (a+b x^3\right )^{10/3}}+\frac{x \left (c+d x^3\right ) (b c-a d)}{13 a b \left (a+b x^3\right )^{13/3}} \]
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Rubi [A] time = 0.127353, antiderivative size = 211, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.19, Rules used = {413, 385, 192, 191} \[ \frac{9 x \left (2 a^2 d^2+9 a b c d+54 b^2 c^2\right )}{910 a^5 b^2 \sqrt [3]{a+b x^3}}+\frac{3 x \left (2 a^2 d^2+9 a b c d+54 b^2 c^2\right )}{910 a^4 b^2 \left (a+b x^3\right )^{4/3}}+\frac{x \left (2 a^2 d^2+9 a b c d+54 b^2 c^2\right )}{455 a^3 b^2 \left (a+b x^3\right )^{7/3}}+\frac{2 x (b c-a d) (a d+3 b c)}{65 a^2 b^2 \left (a+b x^3\right )^{10/3}}+\frac{x \left (c+d x^3\right ) (b c-a d)}{13 a b \left (a+b x^3\right )^{13/3}} \]
Antiderivative was successfully verified.
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Rule 413
Rule 385
Rule 192
Rule 191
Rubi steps
\begin{align*} \int \frac{\left (c+d x^3\right )^2}{\left (a+b x^3\right )^{16/3}} \, dx &=\frac{(b c-a d) x \left (c+d x^3\right )}{13 a b \left (a+b x^3\right )^{13/3}}+\frac{\int \frac{c (12 b c+a d)+d (9 b c+4 a d) x^3}{\left (a+b x^3\right )^{13/3}} \, dx}{13 a b}\\ &=\frac{2 (b c-a d) (3 b c+a d) x}{65 a^2 b^2 \left (a+b x^3\right )^{10/3}}+\frac{(b c-a d) x \left (c+d x^3\right )}{13 a b \left (a+b x^3\right )^{13/3}}+\frac{\left (54 b^2 c^2+9 a b c d+2 a^2 d^2\right ) \int \frac{1}{\left (a+b x^3\right )^{10/3}} \, dx}{65 a^2 b^2}\\ &=\frac{2 (b c-a d) (3 b c+a d) x}{65 a^2 b^2 \left (a+b x^3\right )^{10/3}}+\frac{\left (54 b^2 c^2+9 a b c d+2 a^2 d^2\right ) x}{455 a^3 b^2 \left (a+b x^3\right )^{7/3}}+\frac{(b c-a d) x \left (c+d x^3\right )}{13 a b \left (a+b x^3\right )^{13/3}}+\frac{\left (6 \left (54 b^2 c^2+9 a b c d+2 a^2 d^2\right )\right ) \int \frac{1}{\left (a+b x^3\right )^{7/3}} \, dx}{455 a^3 b^2}\\ &=\frac{2 (b c-a d) (3 b c+a d) x}{65 a^2 b^2 \left (a+b x^3\right )^{10/3}}+\frac{\left (54 b^2 c^2+9 a b c d+2 a^2 d^2\right ) x}{455 a^3 b^2 \left (a+b x^3\right )^{7/3}}+\frac{3 \left (54 b^2 c^2+9 a b c d+2 a^2 d^2\right ) x}{910 a^4 b^2 \left (a+b x^3\right )^{4/3}}+\frac{(b c-a d) x \left (c+d x^3\right )}{13 a b \left (a+b x^3\right )^{13/3}}+\frac{\left (9 \left (54 b^2 c^2+9 a b c d+2 a^2 d^2\right )\right ) \int \frac{1}{\left (a+b x^3\right )^{4/3}} \, dx}{910 a^4 b^2}\\ &=\frac{2 (b c-a d) (3 b c+a d) x}{65 a^2 b^2 \left (a+b x^3\right )^{10/3}}+\frac{\left (54 b^2 c^2+9 a b c d+2 a^2 d^2\right ) x}{455 a^3 b^2 \left (a+b x^3\right )^{7/3}}+\frac{3 \left (54 b^2 c^2+9 a b c d+2 a^2 d^2\right ) x}{910 a^4 b^2 \left (a+b x^3\right )^{4/3}}+\frac{9 \left (54 b^2 c^2+9 a b c d+2 a^2 d^2\right ) x}{910 a^5 b^2 \sqrt [3]{a+b x^3}}+\frac{(b c-a d) x \left (c+d x^3\right )}{13 a b \left (a+b x^3\right )^{13/3}}\\ \end{align*}
Mathematica [A] time = 5.07386, size = 138, normalized size = 0.65 \[ \frac{x \left (9 a^2 b^2 x^6 \left (390 c^2+39 c d x^3+2 d^2 x^6\right )+39 a^3 b x^3 \left (70 c^2+15 c d x^3+2 d^2 x^6\right )+65 a^4 \left (14 c^2+7 c d x^3+2 d^2 x^6\right )+81 a b^3 c x^9 \left (26 c+d x^3\right )+486 b^4 c^2 x^{12}\right )}{910 a^5 \left (a+b x^3\right )^{13/3}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.007, size = 156, normalized size = 0.7 \begin{align*}{\frac{x \left ( 18\,{a}^{2}{b}^{2}{d}^{2}{x}^{12}+81\,a{b}^{3}cd{x}^{12}+486\,{b}^{4}{c}^{2}{x}^{12}+78\,{a}^{3}b{d}^{2}{x}^{9}+351\,{a}^{2}{b}^{2}cd{x}^{9}+2106\,a{b}^{3}{c}^{2}{x}^{9}+130\,{a}^{4}{d}^{2}{x}^{6}+585\,{a}^{3}bcd{x}^{6}+3510\,{a}^{2}{b}^{2}{c}^{2}{x}^{6}+455\,{a}^{4}cd{x}^{3}+2730\,{a}^{3}b{c}^{2}{x}^{3}+910\,{c}^{2}{a}^{4} \right ) }{910\,{a}^{5}} \left ( b{x}^{3}+a \right ) ^{-{\frac{13}{3}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0.977636, size = 284, normalized size = 1.35 \begin{align*} \frac{{\left (35 \, b^{2} - \frac{91 \,{\left (b x^{3} + a\right )} b}{x^{3}} + \frac{65 \,{\left (b x^{3} + a\right )}^{2}}{x^{6}}\right )} d^{2} x^{13}}{455 \,{\left (b x^{3} + a\right )}^{\frac{13}{3}} a^{3}} - \frac{{\left (140 \, b^{3} - \frac{546 \,{\left (b x^{3} + a\right )} b^{2}}{x^{3}} + \frac{780 \,{\left (b x^{3} + a\right )}^{2} b}{x^{6}} - \frac{455 \,{\left (b x^{3} + a\right )}^{3}}{x^{9}}\right )} c d x^{13}}{910 \,{\left (b x^{3} + a\right )}^{\frac{13}{3}} a^{4}} + \frac{{\left (35 \, b^{4} - \frac{182 \,{\left (b x^{3} + a\right )} b^{3}}{x^{3}} + \frac{390 \,{\left (b x^{3} + a\right )}^{2} b^{2}}{x^{6}} - \frac{455 \,{\left (b x^{3} + a\right )}^{3} b}{x^{9}} + \frac{455 \,{\left (b x^{3} + a\right )}^{4}}{x^{12}}\right )} c^{2} x^{13}}{455 \,{\left (b x^{3} + a\right )}^{\frac{13}{3}} a^{5}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.84741, size = 433, normalized size = 2.05 \begin{align*} \frac{{\left (9 \,{\left (54 \, b^{4} c^{2} + 9 \, a b^{3} c d + 2 \, a^{2} b^{2} d^{2}\right )} x^{13} + 39 \,{\left (54 \, a b^{3} c^{2} + 9 \, a^{2} b^{2} c d + 2 \, a^{3} b d^{2}\right )} x^{10} + 65 \,{\left (54 \, a^{2} b^{2} c^{2} + 9 \, a^{3} b c d + 2 \, a^{4} d^{2}\right )} x^{7} + 910 \, a^{4} c^{2} x + 455 \,{\left (6 \, a^{3} b c^{2} + a^{4} c d\right )} x^{4}\right )}{\left (b x^{3} + a\right )}^{\frac{2}{3}}}{910 \,{\left (a^{5} b^{5} x^{15} + 5 \, a^{6} b^{4} x^{12} + 10 \, a^{7} b^{3} x^{9} + 10 \, a^{8} b^{2} x^{6} + 5 \, a^{9} b x^{3} + a^{10}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (d x^{3} + c\right )}^{2}}{{\left (b x^{3} + a\right )}^{\frac{16}{3}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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